What is ln(((x^2+1)(x^4+x^2+1))/(x^4+1)) ?

The solution to ln(((x^2+1)(x^4+x^2+1))/(x^4+1)) is ln(x^2+1)+ln(x^4+x^2+1)-ln(x^4+1)

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simplify ln(((x^2+1)(x^4+x^2+1))/(x^4+1))

simplify

ln (\frac{( x ^{2} + 1 ) ( x ^{4} + x ^{2} + 1 )}{x ^{4} + 1})

ln (x^{2} + 1) + ln (x^{4} + x^{2} + 1) - ln (x^{4} + 1)

Solution steps

ln (\frac{( x ^{2} + 1 ) ( x ^{4} + x ^{2} + 1 )}{x ^{4} + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{( x ^{2} + 1 ) ( x ^{4} + x ^{2} + 1 )}{x ^{4} + 1}) = ln ((x^{2} + 1) (x^{4} + x^{2} + 1)) - ln (x^{4} + 1)

= ln ((x^{2} + 1) (x^{4} + x^{2} + 1)) - ln (x^{4} + 1)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((x^{2} + 1) (x^{4} + x^{2} + 1)) = ln (x^{2} + 1) + ln (x^{4} + x^{2} + 1)

= ln (x^{2} + 1) + ln (x^{4} + x^{2} + 1) - ln (x^{4} + 1)

ln (C e^{\frac{Q}{RT}})

0.55 - \frac{0.591}{1} \cdot lo g_{10} (\frac{0.038}{0.306})

ln (\frac{1}{E})

22 + ln (1 + 2) - ln (- 1 + 2)

- lo g_{10} (0.8 \cdot 1 0^{- 2})

What is ln(((x^2+1)(x^4+x^2+1))/(x^4+1)) ?
The solution to ln(((x^2+1)(x^4+x^2+1))/(x^4+1)) is ln(x^2+1)+ln(x^4+x^2+1)-ln(x^4+1)