What are the solutions to the equation 24^2+x^2=25^2 ?

The solutions to the equation 24^2+x^2=25^2 are x=7,x=-7

Find the zeros of 24^2+x^2=25^2

The zeros of 24^2+x^2=25^2 are x=7,x=-7

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2 4^{2} + x^{2} = 2 5^{2}

x = 7, x = - 7

Solution steps

2 4^{2} + x^{2} = 2 5^{2}

Move

2 4^{2}

to the right side

x^{2} = 49

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 49, x = - 49

49 = 7

- 49 = - 7

x = 7, x = - 7

30 z^{2} + 13 z - 3

63 x^{2} y - 7 y

\frac{\frac{11.94}{0.0125 ( 29 \cdot 1 0 ^{6} )}}{9}

\frac{( x + 1 )}{x - 2} \geq \frac{x}{x - 1}

What are the solutions to the equation 24^2+x^2=25^2 ?
The solutions to the equation 24^2+x^2=25^2 are x=7,x=-7
Find the zeros of 24^2+x^2=25^2
The zeros of 24^2+x^2=25^2 are x=7,x=-7