What is expand log_{3}((wu^6v)^2) ?

The solution to expand log_{3}((wu^6v)^2) is 2log_{3}(w)+12log_{3}(u)+2log_{3}(v)

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expand log_{3}((wu^6v)^2)

expand

lo g_{3} ((w u^{6} v)^{2})

2 lo g_{3} (w) + 12 lo g_{3} (u) + 2 lo g_{3} (v)

Solution steps

lo g_{3} ((w u^{6} v)^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{3} ((w u^{6} v)^{2}) = 2 lo g_{3} (w u^{6} v)

= 2 lo g_{3} (w u^{6} v)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

2 lo g_{3} (w u^{6} v) = 2 lo g_{3} (w) + 2 lo g_{3} (u^{6}) + 2 lo g_{3} (v)

= 2 lo g_{3} (w) + 2 lo g_{3} (u^{6}) + 2 lo g_{3} (v)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{3} (u^{6}) = 6 lo g_{3} (u)

= 2 lo g_{3} (w) + 2 \cdot 6 lo g_{3} (u) + 2 lo g_{3} (v)

Multiply the numbers:

2 \cdot 6 = 12

= 2 lo g_{3} (w) + 12 lo g_{3} (u) + 2 lo g_{3} (v)

- ln (7.2 e^{- 4})

3 lo g_{b} (x) + \frac{1}{2} lo g_{b} (y)

lo g_{8} (x) - lo g_{8} (50)

\frac{18}{5} lo g_{\frac{4}{5}} (2)

ln (y - 2) + ln (y + 2)

What is expand log_{3}((wu^6v)^2) ?
The solution to expand log_{3}((wu^6v)^2) is 2log_{3}(w)+12log_{3}(u)+2log_{3}(v)