What is 2log_{0.29}(2)-log_{0.29}(13) ?

The solution to 2log_{0.29}(2)-log_{0.29}(13) is log_{0.29}(4/13)

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simplify 2log_{0.29}(2)-log_{0.29}(13)

simplify

2 lo g_{0.29} (2) - lo g_{0.29} (13)

lo g_{0.29} (\frac{4}{13})

Decimal Notation

0.95216 \dots

Solution steps

2 lo g_{0.29} (2) - lo g_{0.29} (13)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{0.29} (2) = lo g_{0.29} (2^{2})

= lo g_{0.29} (2^{2}) - lo g_{0.29} (13)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{0.29} (2^{2}) - lo g_{0.29} (13) = lo g_{0.29} (\frac{2 ^{2}}{13})

= lo g_{0.29} (\frac{2 ^{2}}{13})

2^{2} = 4

= lo g_{0.29} (\frac{4}{13})

lo g_{10} (x^{2} y z^{3})

(ln (1.3) - ln (0.54)) \cdot 182000

ln (\frac{y ^{3}}{7})

lo g_{w} (\frac{13 w}{2})

- lo g_{10} (2.19 \cdot 1 0^{- 3})

What is 2log_{0.29}(2)-log_{0.29}(13) ?
The solution to 2log_{0.29}(2)-log_{0.29}(13) is log_{0.29}(4/13)