What are the solutions to the equation 3(x+7)^2=54 ?

The solutions to the equation 3(x+7)^2=54 are x=3sqrt(2)-7,x=-3sqrt(2)-7

Find the zeros of 3(x+7)^2=54

The zeros of 3(x+7)^2=54 are x=3sqrt(2)-7,x=-3sqrt(2)-7

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3 (x + 7)^{2} = 54

x = 32 - 7, x = - 32 - 7

Decimal Notation

x = - 2.75735 \dots, x = - 11.24264 \dots

Solution steps

3 (x + 7)^{2} = 54

Divide both sides by

3

(x + 7)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 7 = 18 : x = 32 - 7

Solve

x + 7 = - 18 : x = - 32 - 7

The solutions to the quadratic equation are:

x = 32 - 7, x = - 32 - 7

\frac{1 - i}{1 + i}

7 x - 3 > 18

∣ x - 4 ∣ < 10

\frac{34 x ^{2}}{2 \cdot 2.6} = 9.8 x

∣ 6 p + 5 ∣ + 3 < 17

What are the solutions to the equation 3(x+7)^2=54 ?
The solutions to the equation 3(x+7)^2=54 are x=3sqrt(2)-7,x=-3sqrt(2)-7
Find the zeros of 3(x+7)^2=54
The zeros of 3(x+7)^2=54 are x=3sqrt(2)-7,x=-3sqrt(2)-7