What is 1/4 ln(6ba^2)-ln(m)-1/4 ln(5) ?

The solution to 1/4 ln(6ba^2)-ln(m)-1/4 ln(5) is ln((\sqrt[4]{6}*5^{3/4}\sqrt[4]{ba^2})/(5m))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/4 ln(6ba^2)-ln(m)-1/4 ln(5)

simplify

\frac{1}{4} ln (6 b a^{2}) - ln (m) - \frac{1}{4} ln (5)

ln (\frac{4 6 \cdot 5 ^{\frac{3}{4}} 4 b a ^{2}}{5 m})

Solution steps

\frac{1}{4} ln (6 b a^{2}) - ln (m) - \frac{1}{4} ln (5)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{4} ln (6 b a^{2}) = ln ((6 b a^{2})^{\frac{1}{4}})

= ln ((6 b a^{2})^{\frac{1}{4}}) - ln (m) - \frac{1}{4} ln (5)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ((6 b a^{2})^{\frac{1}{4}}) - ln (m) = ln \frac{( 6 b a ^{2} ) ^{\frac{1}{4}}}{m}

= ln \frac{( 6 b a ^{2} ) ^{\frac{1}{4}}}{m} - \frac{1}{4} ln (5)

(6 b a^{2})^{\frac{1}{4}} = 46 4 b a^{2}

= ln (\frac{4 6 4 b a ^{2}}{m}) - \frac{1}{4} ln (5)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{4} ln (5) = ln (5^{\frac{1}{4}})

= ln (\frac{4 6 4 b a ^{2}}{m}) - ln (5^{\frac{1}{4}})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (\frac{4 6 4 b a ^{2}}{m}) - ln (5^{\frac{1}{4}}) = ln (\frac{\frac{4 6 4 b a ^{2}}{m}}{5 ^{\frac{1}{4}}})

= ln (\frac{\frac{4 6 4 b a ^{2}}{m}}{5 ^{\frac{1}{4}}})

Simplify

\frac{\frac{4 6 4 b a ^{2}}{m}}{5 ^{\frac{1}{4}}} : \frac{4 6 \cdot 5 ^{\frac{3}{4}} 4 b a ^{2}}{5 m}

= ln (\frac{4 6 \cdot 5 ^{\frac{3}{4}} 4 b a ^{2}}{5 m})

- lo g_{10} (2.19 \cdot 1 0^{- 6})

ln (1 - x) - ln (1 - y)

0 ln (\frac{500}{z})

\frac{ln ( 4.1 ) - ln ( 3.9 )}{2 \cdot 0.1}

\frac{1}{19} ln (\frac{34}{19})

What is 1/4 ln(6ba^2)-ln(m)-1/4 ln(5) ?
The solution to 1/4 ln(6ba^2)-ln(m)-1/4 ln(5) is ln((\sqrt[4]{6}*5^{3/4}\sqrt[4]{ba^2})/(5m))