What is join-(ln(2)ln(-1))/(2pi) ?

The solution to join-(ln(2)ln(-1))/(2pi) is -(ln((-1)^{ln(2)}))/(2pi)

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join-(ln(2)ln(-1))/(2pi)

join

- \frac{ln ( 2 ) ln ( - 1 )}{2 π}

- \frac{ln ( ( - 1 ) ^{l n (2)} )}{2 π}

Solution steps

- \frac{ln ( 2 ) ln ( - 1 )}{2 π}

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

ln (2) ln (- 1) = ln ((- 1)^{l n (2)})

= - \frac{ln ( ( - 1 ) ^{l n (2)} )}{2 π}

3 ln ∣ x - 2 ∣ - ln ∣ x + 3 ∣

- lo g_{10} (7.2 \cdot 1 0^{-} 14)

50 (\frac{1}{25} ln ∣ x ∣ - \frac{1}{25} ln ∣ x + 25 ∣)^{'}

ln (18) + ln (7) - ln (20)

lo g_{10} (\frac{y ^{5}}{3 x})

What is join-(ln(2)ln(-1))/(2pi) ?
The solution to join-(ln(2)ln(-1))/(2pi) is -(ln((-1)^{ln(2)}))/(2pi)