What is 1/3 (log_{a}(2x^2)-log_{a}(by^5)) ?

The solution to 1/3 (log_{a}(2x^2)-log_{a}(by^5)) is 1/3 log_{a}((2x^2)/(by^5))

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simplify 1/3 (log_{a}(2x^2)-log_{a}(by^5))

simplify

\frac{1}{3} (lo g_{a} (2 x^{2}) - lo g_{a} (b y^{5}))

\frac{1}{3} lo g_{a} (\frac{2 x ^{2}}{b y ^{5}})

Solution steps

\frac{1}{3} (lo g_{a} (2 x^{2}) - lo g_{a} (b y^{5}))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{a} (2 x^{2}) - lo g_{a} (b y^{5}) = lo g_{a} (\frac{2 x ^{2}}{b y ^{5}})

= \frac{1}{3} lo g_{a} (\frac{2 x ^{2}}{b y ^{5}})

ln (ib)

- lo g_{10} (4.56 \cdot 1 0^{- 6})

\frac{1}{3} ln (\frac{5 + 1}{5 - 2})

- 98.97 \cdot ln (\frac{0.1}{10})

2 ln ∣ l + d ∣ - ln ∣ d ∣ - ln ∣ 2 l + d ∣

What is 1/3 (log_{a}(2x^2)-log_{a}(by^5)) ?
The solution to 1/3 (log_{a}(2x^2)-log_{a}(by^5)) is 1/3 log_{a}((2x^2)/(by^5))