What are the solutions to the equation w^2-31w=132 ?

The solutions to the equation w^2-31w=132 are w=(31+sqrt(1489))/2 ,w=(31-sqrt(1489))/2

Find the zeros of w^2-31w=132

The zeros of w^2-31w=132 are w=(31+sqrt(1489))/2 ,w=(31-sqrt(1489))/2

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w^{2} - 31 w = 132

w = \frac{31 + 1489}{2}, w = \frac{31 - 1489}{2}

Solution steps

w^{2} - 31 w = 132

Move

132

to the left side

w^{2} - 31 w - 132 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 31 ) \pm ( - 31 ) ^{2} - 4 \cdot 1 \cdot ( - 132 )}{2 \cdot 1}

(- 31)^{2} - 4 \cdot 1 \cdot (- 132) = 1489

w_{1, 2} = \frac{- ( - 31 ) \pm 1489}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- ( - 31 ) + 1489}{2 \cdot 1}, w_{2} = \frac{- ( - 31 ) - 1489}{2 \cdot 1}

w = \frac{- ( - 31 ) + 1489}{2 \cdot 1} : \frac{31 + 1489}{2}

w = \frac{- ( - 31 ) - 1489}{2 \cdot 1} : \frac{31 - 1489}{2}

The solutions to the quadratic equation are:

w = \frac{31 + 1489}{2}, w = \frac{31 - 1489}{2}

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56 b + 14 c

∣ x + 7 ∣ < 5

2 x^{2} - 25 x - 13

What are the solutions to the equation w^2-31w=132 ?
The solutions to the equation w^2-31w=132 are w=(31+sqrt(1489))/2 ,w=(31-sqrt(1489))/2
Find the zeros of w^2-31w=132
The zeros of w^2-31w=132 are w=(31+sqrt(1489))/2 ,w=(31-sqrt(1489))/2