What is (3)(e^{0.6x})+9ln(2x^5)+(8)cos(2x)-9 ?

The solution to (3)(e^{0.6x})+9ln(2x^5)+(8)cos(2x)-9 is 3e^{0.6x}+9ln(2)+45ln(x)+8cos(2x)-9

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simplify (3)(e^{0.6x})+9ln(2x^5)+(8)cos(2x)-9

simplify

(3) (e^{0.6 x}) + 9 ln (2 x^{5}) + (8) cos (2 x) - 9

3 e^{0.6 x} + 9 ln (2) + 45 ln (x) + 8 cos (2 x) - 9

Solution steps

(3) (e^{0.6 x}) + 9 ln (2 x^{5}) + (8) cos (2 x) - 9

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

9 ln (2 x^{5}) = 9 ln (2) + 9 ln (x^{5})

= (3) (e^{0.6 x}) + 9 ln (2) + 9 ln (x^{5}) + (8) cos (2 x) - 9

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (x^{5}) = 5 ln (x)

= 3 e^{0.6 x} + 9 ln (2) + 9 \cdot 5 ln (x) + 8 cos (2 x) - 9

Multiply the numbers:

9 \cdot 5 = 45

= 3 e^{0.6 x} + 9 ln (2) + 45 ln (x) + 8 cos (2 x) - 9

- ln (\frac{3.8}{16})

lo g_{e} (8) + lo g_{e} (70)

ln (x r^{x})

lo g_{1.8} (\frac{4.22}{3.13}) + 55.28 - 55.02

ln (\frac{55}{7})

What is (3)(e^{0.6x})+9ln(2x^5)+(8)cos(2x)-9 ?
The solution to (3)(e^{0.6x})+9ln(2x^5)+(8)cos(2x)-9 is 3e^{0.6x}+9ln(2)+45ln(x)+8cos(2x)-9