What is ln(1/(2e^{x^2)})+ln(c) ?

The solution to ln(1/(2e^{x^2)})+ln(c) is ln(c/(2e^{x^2)})

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simplify ln(1/(2e^{x^2)})+ln(c)

simplify

ln (\frac{1}{2 e ^{x^{2}}}) + ln (c)

ln (\frac{c}{2 e ^{x^{2}}})

Solution steps

ln (\frac{1}{2 e ^{x^{2}}}) + ln (c)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (\frac{1}{2 e ^{x^{2}}}) + ln (c) = ln (c \frac{1}{2 e ^{x^{2}}})

= ln (c \frac{1}{2 e ^{x^{2}}})

Simplify

\frac{1}{2 e ^{x^{2}}} c : \frac{c}{2 e ^{x^{2}}}

= ln (\frac{c}{2 e ^{x^{2}}})

\frac{1}{4} ln (\frac{2 - 1}{2 + 1})

4 lo g_{10} (x - 6) - 5 lo g_{10} (x)

3 (lo g_{2} (x) - 4 lo g_{2} (y)) + 2 lo g_{2} (w)

ln ∣ x + 1 ∣ - ln ∣ x + 2 ∣

ln (\frac{81 + 273}{22 + 273})

What is ln(1/(2e^{x^2)})+ln(c) ?
The solution to ln(1/(2e^{x^2)})+ln(c) is ln(c/(2e^{x^2)})