What is 2log_{a}(t-log_{a}(s)+4log_{a}(u)) ?

The solution to 2log_{a}(t-log_{a}(s)+4log_{a}(u)) is 2log_{a}(t+log_{a}((u^4)/s))

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simplify 2log_{a}(t-log_{a}(s)+4log_{a}(u))

simplify

2 lo g_{a} (t - lo g_{a} (s) + 4 lo g_{a} (u))

2 lo g_{a} (t + lo g_{a} (\frac{u ^{4}}{s}))

Solution steps

2 lo g_{a} (t - lo g_{a} (s) + 4 lo g_{a} (u))

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{a} (u) = lo g_{a} (u^{4})

= 2 lo g_{a} (t + lo g_{a} (u^{4}) - lo g_{a} (s))

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{a} (u^{4}) - lo g_{a} (s) = lo g_{a} (\frac{u ^{4}}{s})

= 2 lo g_{a} (t + lo g_{a} (\frac{u ^{4}}{s}))

ln (1 0^{- 4}) - 3.82 ln (15)

\frac{1}{0.013} ln (\frac{42}{34})

3 ln (x) - 4 ln (x + 3) + ln (y)

- 8000 \cdot ln (\frac{400}{1000})

ln (x^{a - 1} (1 - x)^{b - 1})

What is 2log_{a}(t-log_{a}(s)+4log_{a}(u)) ?
The solution to 2log_{a}(t-log_{a}(s)+4log_{a}(u)) is 2log_{a}(t+log_{a}((u^4)/s))