What is ln((n+1)^2)-ln(n^2) ?

The solution to ln((n+1)^2)-ln(n^2) is ln(((n+1)^2)/(n^2))

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simplify ln((n+1)^2)-ln(n^2)

simplify

ln ((n + 1)^{2}) - ln (n^{2})

ln (\frac{( n + 1 ) ^{2}}{n ^{2}})

Solution steps

ln ((n + 1)^{2}) - ln (n^{2})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ((n + 1)^{2}) - ln (n^{2}) = ln (\frac{( n + 1 ) ^{2}}{n ^{2}})

= ln (\frac{( n + 1 ) ^{2}}{n ^{2}})

ln (\frac{0.55}{1.3})

2 ln (\frac{\frac{1}{2} - 1}{\frac{1}{2} + 1})

- lo g_{10} (3.62 \cdot 1 0^{- 2})

ln (- 9 e)

ln (1.999 - 2) - ln (1.999 + 1)

What is ln((n+1)^2)-ln(n^2) ?
The solution to ln((n+1)^2)-ln(n^2) is ln(((n+1)^2)/(n^2))