What are the solutions to the equation h^2+7h=44 ?

The solutions to the equation h^2+7h=44 are h=4,h=-11

Find the zeros of h^2+7h=44

The zeros of h^2+7h=44 are h=4,h=-11

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h^{2} + 7 h = 44

h = 4, h = - 11

Solution steps

h^{2} + 7 h = 44

Move

44

to the left side

h^{2} + 7 h - 44 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 44) = 15

h_{1, 2} = \frac{- 7 \pm 15}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- 7 + 15}{2 \cdot 1}, h_{2} = \frac{- 7 - 15}{2 \cdot 1}

h = \frac{- 7 + 15}{2 \cdot 1} : 4

h = \frac{- 7 - 15}{2 \cdot 1} : - 11

The solutions to the quadratic equation are:

h = 4, h = - 11

x^{2} - 3 x = 5

∣ 2 - 16 x ∣ < - 13

4 x^{2} + 19 x - 22 = 0

\frac{( 4 + 4 i )}{( 5 + 4 i )}

- \frac{2}{3} - 4

What are the solutions to the equation h^2+7h=44 ?
The solutions to the equation h^2+7h=44 are h=4,h=-11
Find the zeros of h^2+7h=44
The zeros of h^2+7h=44 are h=4,h=-11