What is log_{e}(9)+log_{e}(2) ?

The solution to log_{e}(9)+log_{e}(2) is ln(18)

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simplify log_{e}(9)+log_{e}(2)

simplify

lo g_{e} (9) + lo g_{e} (2)

ln (18)

Decimal Notation

2.89037 \dots

Solution steps

lo g_{e} (9) + lo g_{e} (2)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{e} (9) + lo g_{e} (2) = lo g_{e} (9 \cdot 2)

= lo g_{e} (9 \cdot 2)

Multiply the numbers:

9 \cdot 2 = 18

= lo g_{e} (18)

Apply log rule:

lo g_{e} (x) = ln (x)

= ln (18)

ln (\frac{1}{2} x - 3 + x^{2} - 6 x + 13)

3 lo g_{9} (a) - 12 lo g_{9} (b)

3 ln ∣ x ∣ - 2 ln ∣ x + 11 ∣

\frac{3}{2} ln (t) + \frac{1}{2} ln (b) - 2 + ln (e^{2}) - 8 ln (m)

ln (800 e^{0.05 t}) - ln (220 e^{- 0.05 t})