What is ln((x^2+1)^2)+ln(((x+1)/(x-1))^2) ?

The solution to ln((x^2+1)^2)+ln(((x+1)/(x-1))^2) is ln(((x+1)^2(x^2+1)^2)/((x-1)^2))

Popular >

simplify ln((x^2+1)^2)+ln(((x+1)/(x-1))^2)

simplify

ln ((x^{2} + 1)^{2}) + ln ((\frac{x + 1}{x - 1})^{2})

ln (\frac{( x + 1 ) ^{2} ( x ^{2} + 1 ) ^{2}}{( x - 1 ) ^{2}})

Solution steps

ln ((x^{2} + 1)^{2}) + ln ((\frac{x + 1}{x - 1})^{2})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln ((x^{2} + 1)^{2}) + ln ((\frac{x + 1}{x - 1})^{2}) = ln ((\frac{x + 1}{x - 1})^{2} (x^{2} + 1)^{2})

= ln ((\frac{x + 1}{x - 1})^{2} (x^{2} + 1)^{2})

Simplify

(x^{2} + 1)^{2} (\frac{x + 1}{x - 1})^{2} : \frac{( x + 1 ) ^{2} ( x ^{2} + 1 ) ^{2}}{( x - 1 ) ^{2}}

= ln (\frac{( x + 1 ) ^{2} ( x ^{2} + 1 ) ^{2}}{( x - 1 ) ^{2}})

lo g_{5} (7 \cdot 3)

7 lo g_{3} (y) - \frac{1}{4} lo g_{3} (z) + 2 lo g_{3} (x)

ln ∣ x + 2 ∣ - \frac{1}{2} ln y^{2} - 1

lo g_{10} (\frac{x ^{3} y}{z})

0.0296 \cdot 46 e^{(\frac{l n ( 263 ) - l n ( 46 )}{30}) 3}

What is ln((x^2+1)^2)+ln(((x+1)/(x-1))^2) ?
The solution to ln((x^2+1)^2)+ln(((x+1)/(x-1))^2) is ln(((x+1)^2(x^2+1)^2)/((x-1)^2))