What are the solutions to the equation 4(x-2)^2=25 ?

The solutions to the equation 4(x-2)^2=25 are x= 9/2 ,x=-1/2

Find the zeros of 4(x-2)^2=25

The zeros of 4(x-2)^2=25 are x= 9/2 ,x=-1/2

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4 (x - 2)^{2} = 25

x = \frac{9}{2}, x = - \frac{1}{2}

Solution steps

4 (x - 2)^{2} = 25

Divide both sides by

4

(x - 2)^{2} = \frac{25}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = \frac{25}{4} : x = \frac{9}{2}

Solve

x - 2 = - \frac{25}{4} : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - \frac{1}{2}

\frac{- 5}{5}

b + (- 6) + 13 = 25

2 x^{(2)} + 5 x + 2 > 0

\frac{2 x - 1}{x} < 3

9 + 9 n = 9

What are the solutions to the equation 4(x-2)^2=25 ?
The solutions to the equation 4(x-2)^2=25 are x= 9/2 ,x=-1/2
Find the zeros of 4(x-2)^2=25
The zeros of 4(x-2)^2=25 are x= 9/2 ,x=-1/2