What is ln(0.12x)+4-(0.6x-0.7)^3 ?

The solution to ln(0.12x)+4-(0.6x-0.7)^3 is -0.216x^3+0.756x^2-0.882x+ln(x)+4.343+ln(0.12)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(0.12x)+4-(0.6x-0.7)^3

simplify

ln (0.12 x) + 4 - (0.6 x - 0.7)^{3}

- 0.216 x^{3} + 0.756 x^{2} - 0.882 x + ln (x) + 4.343 + ln (0.12)

Solution steps

ln (0.12 x) + 4 - (0.6 x - 0.7)^{3}

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (0.12 x) = ln (0.12) + ln (x)

= ln (0.12) + ln (x) + 4 - (0.6 x - 0.7)^{3}

(0.6 x - 0.7)^{3} : 0.216 x^{3} - 0.756 x^{2} + 0.882 x - 0.343

= ln (0.12) + ln (x) + 4 - (0.216 x^{3} - 0.756 x^{2} + 0.882 x - 0.343)

- (0.216 x^{3} - 0.756 x^{2} + 0.882 x - 0.343) : - 0.216 x^{3} + 0.756 x^{2} - 0.882 x + 0.343

= ln (0.12) + ln (x) + 4 - 0.216 x^{3} + 0.756 x^{2} - 0.882 x + 0.343

Simplify

ln (0.12) + ln (x) + 4 - 0.216 x^{3} + 0.756 x^{2} - 0.882 x + 0.343 : - 0.216 x^{3} + 0.756 x^{2} - 0.882 x + ln (x) + 4.343 + ln (0.12)

= - 0.216 x^{3} + 0.756 x^{2} - 0.882 x + ln (x) + 4.343 + ln (0.12)

ln (\frac{0.001}{0.1})

\frac{1}{8} ln (3)

lo g_{10} (\frac{1}{2 \cdot 1 0 ^{- 2}})

ln (\frac{x ^{2}}{y ^{5}})

2 lo g_{b} (z) - \frac{1}{2} lo g_{b} (y) + 4 lo g_{b} (x)

What is ln(0.12x)+4-(0.6x-0.7)^3 ?
The solution to ln(0.12x)+4-(0.6x-0.7)^3 is -0.216x^3+0.756x^2-0.882x+ln(x)+4.343+ln(0.12)