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Popular >

simplify ln|x|-ln|x^2+1|

Solution

simplify

ln ∣ x ∣ - ln x^{2} + 1

Solution

ln (\frac{∣ x ∣}{∣ x ^{2} + 1 ∣})

Solution steps

ln ∣ x ∣ - ln x^{2} + 1

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ x ∣ - ln x^{2} + 1 = ln (\frac{∣ x ∣}{∣ x ^{2} + 1 ∣})

= ln (\frac{∣ x ∣}{∣ x ^{2} + 1 ∣})

Popular Examples

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20 \cdot lo g_{10} (\frac{4 \cdot π \cdot 30}{\frac{300}{175}})

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\frac{100}{7} ln (5)

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lo g_{\frac{1}{2}} (1 \cdot 1 0^{- 9})

Frequently Asked Questions (FAQ)

What is ln|x|-ln|x^2+1| ?
The solution to ln|x|-ln|x^2+1| is ln((|x|)/(|x^2+1|))