What is (ln(1-x^2)-ln(1+x^2))^2 ?

The solution to (ln(1-x^2)-ln(1+x^2))^2 is ln^2((1-x^2)/(1+x^2))

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simplify (ln(1-x^2)-ln(1+x^2))^2

simplify

(ln (1 - x^{2}) - ln (1 + x^{2}))^{2}

ln^{2} (\frac{1 - x ^{2}}{1 + x ^{2}})

Solution steps

(ln (1 - x^{2}) - ln (1 + x^{2}))^{2}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (1 - x^{2}) - ln (1 + x^{2}) = ln (\frac{- x ^{2} + 1}{x ^{2} + 1})

= ln^{2} (\frac{1 - x ^{2}}{1 + x ^{2}})

ln (cos (2 x) \frac{x + 4}{x})

ln (4) - ln (9 - 4)

- ln (5.4 - 3) + 2 ln (5.4 - 2) + c

ln (3) + 3 ln (2)

182000 (ln (0.41) - ln (1.3))

What is (ln(1-x^2)-ln(1+x^2))^2 ?
The solution to (ln(1-x^2)-ln(1+x^2))^2 is ln^2((1-x^2)/(1+x^2))