What is expand log_{10}(8/(3^2)) ?

The solution to expand log_{10}(8/(3^2)) is 3log_{10}(2)-2log_{10}(3)

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expand log_{10}(8/(3^2))

expand

lo g_{10} (\frac{8}{3 ^{2}})

3 lo g_{10} (2) - 2 lo g_{10} (3)

Decimal Notation

- 0.05115 \dots

Solution steps

lo g_{10} (\frac{8}{3 ^{2}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{8}{3 ^{2}}) = lo g_{10} (8) - lo g_{10} (3^{2})

= lo g_{10} (8) - lo g_{10} (3^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (3^{2}) = 2 lo g_{10} (3)

= lo g_{10} (8) - 2 lo g_{10} (3)

lo g_{10} (8) = 3 lo g_{10} (2)

= 3 lo g_{10} (2) - 2 lo g_{10} (3)

- ln (x) + ln^{2} (x)

ln (\frac{x - y}{x ^{2} + y ^{2}})

ln (\frac{tan ^{5} ( x )}{e ^{6 x^{4}} x ^{6}})

2 lo g_{10} (x) - lo g_{10} (x + 2)

- ln 900 - x^{2} + 2 ln (30)

What is expand log_{10}(8/(3^2)) ?
The solution to expand log_{10}(8/(3^2)) is 3log_{10}(2)-2log_{10}(3)