What are the solutions to the equation 25x^2-30x+9=81 ?

The solutions to the equation 25x^2-30x+9=81 are x= 12/5 ,x=-6/5

Find the zeros of 25x^2-30x+9=81

The zeros of 25x^2-30x+9=81 are x= 12/5 ,x=-6/5

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25 x^{2} - 30 x + 9 = 81

x = \frac{12}{5}, x = - \frac{6}{5}

Solution steps

25 x^{2} - 30 x + 9 = 81

Move

81

to the left side

25 x^{2} - 30 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 30 ) \pm ( - 30 ) ^{2} - 4 \cdot 25 ( - 72 )}{2 \cdot 25}

(- 30)^{2} - 4 \cdot 25 (- 72) = 90

x_{1, 2} = \frac{- ( - 30 ) \pm 90}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 30 ) + 90}{2 \cdot 25}, x_{2} = \frac{- ( - 30 ) - 90}{2 \cdot 25}

x = \frac{- ( - 30 ) + 90}{2 \cdot 25} : \frac{12}{5}

x = \frac{- ( - 30 ) - 90}{2 \cdot 25} : - \frac{6}{5}

The solutions to the quadratic equation are:

x = \frac{12}{5}, x = - \frac{6}{5}

\frac{x}{9} + 7 = - 4

ln (x) \leq 1

4 x^{2} - 2 x - 12

x^{2} - 5 x + 6 > 0

4 - 3600 \cdot x^{2} = 0

What are the solutions to the equation 25x^2-30x+9=81 ?
The solutions to the equation 25x^2-30x+9=81 are x= 12/5 ,x=-6/5
Find the zeros of 25x^2-30x+9=81
The zeros of 25x^2-30x+9=81 are x= 12/5 ,x=-6/5