What are the solutions to the equation 25x^2-15x+2=0 ?

The solutions to the equation 25x^2-15x+2=0 are x= 2/5 ,x= 1/5

Find the zeros of 25x^2-15x+2=0

The zeros of 25x^2-15x+2=0 are x= 2/5 ,x= 1/5

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25 x^{2} - 15 x + 2 = 0

x = \frac{2}{5}, x = \frac{1}{5}

Solution steps

25 x^{2} - 15 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 25 \cdot 2}{2 \cdot 25}

(- 15)^{2} - 4 \cdot 25 \cdot 2 = 5

x_{1, 2} = \frac{- ( - 15 ) \pm 5}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5}{2 \cdot 25}, x_{2} = \frac{- ( - 15 ) - 5}{2 \cdot 25}

x = \frac{- ( - 15 ) + 5}{2 \cdot 25} : \frac{2}{5}

x = \frac{- ( - 15 ) - 5}{2 \cdot 25} : \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = \frac{1}{5}

\frac{x}{2} - 3 = 5 - x

5 - 2 x = 3 x

(4 - 4 i)^{3}

\frac{8 x ^{5} y ^{4}}{4 x ^{2} y ^{2}}

- 3 x^{2} + 3 x + 6

What are the solutions to the equation 25x^2-15x+2=0 ?
The solutions to the equation 25x^2-15x+2=0 are x= 2/5 ,x= 1/5
Find the zeros of 25x^2-15x+2=0
The zeros of 25x^2-15x+2=0 are x= 2/5 ,x= 1/5