What is ((ln(0-1)-ln(10^{-10})))/(ln(2)) ?

The solution to ((ln(0-1)-ln(10^{-10})))/(ln(2)) is (ln(-10^{10}))/(ln(2))

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simplify ((ln(0-1)-ln(10^{-10})))/(ln(2))

simplify

\frac{( ln ( 0 - 1 ) - ln ( 1 0 ^{- 10} ) )}{ln ( 2 )}

\frac{ln ( - 1 0 ^{10} )}{ln ( 2 )}

Decimal Notation

33.21928 \dots

Solution steps

\frac{( ln ( 0 - 1 ) - ln ( 1 0 ^{- 10} ) )}{ln ( 2 )}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (0 - 1) - ln (1 0^{- 10}) = ln (\frac{0 - 1}{1 0 ^{- 10}})

= \frac{ln ( \frac{0 - 1}{1 0 ^{- 10}} )}{ln ( 2 )}

\frac{0 - 1}{1 0 ^{- 10}} = - 1 0^{10}

= \frac{ln ( - 1 0 ^{10} )}{ln ( 2 )}

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What is ((ln(0-1)-ln(10^{-10})))/(ln(2)) ?
The solution to ((ln(0-1)-ln(10^{-10})))/(ln(2)) is (ln(-10^{10}))/(ln(2))