What is 2400+1/(7.13*10^{-4)}*ln(1/(0.9)) ?

The solution to 2400+1/(7.13*10^{-4)}*ln(1/(0.9)) is 2400-(10000)/(7.13)ln(0.9)

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simplify 2400+1/(7.1310^{-4)}ln(1/(0.9))

simplify

2400 + \frac{1}{7.13 \cdot 1 0 ^{- 4}} \cdot ln (\frac{1}{0.9})

2400 - \frac{10000}{7.13} ln (0.9)

Decimal Notation

2547.77070 \dots

Solution steps

2400 + \frac{1}{7.13 \cdot 1 0 ^{- 4}} ln (\frac{1}{0.9})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{0.9}) = ln (1) - ln (0.9)

= 2400 + \frac{1}{1 0 ^{- 4} \cdot 7.13} (ln (1) - ln (0.9))

\frac{1}{7.13 \cdot 1 0 ^{- 4}} (ln (1) - ln (0.9)) = - \frac{10000}{7.13} ln (0.9)

= 2400 - \frac{10000}{7.13} ln (0.9)

- ln (x) + 2 ln (x + 1)

ln (\frac{b}{x}) + ln (\frac{a}{x})

ln (x - 3) + ln (x + 5) - 2 ln (x)

ln (e^{5 x + 9}) - 4 ln^{3 x + 6} (x)

4 - 2 ln (\frac{2 + 1}{2 - 1})

What is 2400+1/(7.13*10^{-4)}*ln(1/(0.9)) ?
The solution to 2400+1/(7.13*10^{-4)}*ln(1/(0.9)) is 2400-(10000)/(7.13)ln(0.9)