What is log_{10}(2)-log_{10}(1.26) ?

The solution to log_{10}(2)-log_{10}(1.26) is log_{10}(1.58730…)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(2)-log_{10}(1.26)

simplify

lo g_{10} (2) - lo g_{10} (1.26)

lo g_{10} (1.58730 \dots)

Decimal Notation

0.20065 \dots

Solution steps

lo g_{10} (2) - lo g_{10} (1.26)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (2) - lo g_{10} (1.26) = lo g_{10} (\frac{2}{1.26})

= lo g_{10} (\frac{2}{1.26})

Divide the numbers:

\frac{2}{1.26} = 1.58730 \dots

= lo g_{10} (1.58730 \dots)

lo g_{4} (x^{4} \cdot y)

3 lo g_{10} (x + 2) - lo g_{10} (2 x - 3)

ln (\frac{x ^{2} x ^{2} + 4}{( x + 4 ) ^{5}})

(\frac{1}{54}) ln (\frac{65467}{29})

What is log_{10}(2)-log_{10}(1.26) ?
The solution to log_{10}(2)-log_{10}(1.26) is log_{10}(1.58730…)