What is 2log_{10}(a)+log_{10}(b)-3log_{10}(c) ?

The solution to 2log_{10}(a)+log_{10}(b)-3log_{10}(c) is log_{10}((a^2b)/(c^3))

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simplify 2log_{10}(a)+log_{10}(b)-3log_{10}(c)

simplify

2 lo g_{10} (a) + lo g_{10} (b) - 3 lo g_{10} (c)

lo g_{10} (\frac{a ^{2} b}{c ^{3}})

Solution steps

2 lo g_{10} (a) + lo g_{10} (b) - 3 lo g_{10} (c)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (a) = lo g_{10} (a^{2})

= lo g_{10} (a^{2}) + lo g_{10} (b) - 3 lo g_{10} (c)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (a^{2}) + lo g_{10} (b) = lo g_{10} (a^{2} b)

= lo g_{10} (a^{2} b) - 3 lo g_{10} (c)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{10} (c) = lo g_{10} (c^{3})

= lo g_{10} (a^{2} b) - lo g_{10} (c^{3})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (a^{2} b) - lo g_{10} (c^{3}) = lo g_{10} (\frac{a ^{2} b}{c ^{3}})

= lo g_{10} (\frac{a ^{2} b}{c ^{3}})

- lo g_{10} (6.8 \cdot 1 0^{- 6})

\frac{d}{d u} ((t) (ln (t^{2}) + 2 ln (t) + 2))

ln (\frac{1 + 0.85}{1 - 85})

\frac{1}{3} ln f^{7} (x) + \frac{29}{21} ln ∣ f (x) + 15 ∣ + C

0.6 \cdot lo g_{2} (0.6) + 0.4 \cdot lo g_{2} (0.4)

What is 2log_{10}(a)+log_{10}(b)-3log_{10}(c) ?
The solution to 2log_{10}(a)+log_{10}(b)-3log_{10}(c) is log_{10}((a^2b)/(c^3))