What is 20e^{3(3)}-ln|3-9|+2ln(3)+50 ?

The solution to 20e^{3(3)}-ln|3-9|+2ln(3)+50 is 20e^9+ln(3/2)+50

Popular >

simplify 20e^{3(3)}-ln|3-9|+2ln(3)+50

simplify

20 e^{3 (3)} - ln ∣ 3 - 9 ∣ + 2 ln (3) + 50

20 e^{9} + ln (\frac{3}{2}) + 50

Decimal Notation

162112.08401 \dots

Solution steps

20 e^{3 (3)} - ln ∣ 3 - 9 ∣ + 2 ln (3) + 50

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (3) = ln (3^{2})

= 20 e^{3 (3)} - ln ∣ 3 - 9 ∣ + ln (3^{2}) + 50

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (3^{2}) - ln ∣ 3 - 9 ∣ = ln (\frac{3 ^{2}}{∣ 3 - 9 ∣})

= 20 e^{3 \cdot 3} + ln (\frac{3 ^{2}}{∣ 3 - 9 ∣}) + 50

\frac{3 ^{2}}{∣ 3 - 9 ∣} = \frac{3}{2}

= 20 e^{3 \cdot 3} + ln (\frac{3}{2}) + 50

Multiply the numbers:

3 \cdot 3 = 9

= 20 e^{9} + ln (\frac{3}{2}) + 50

\frac{1}{4} lo g_{10} (x) - \frac{1}{4} lo g_{10} (y)

lo g_{10} (3 x - 1) + lo g_{10} (x - 1)

lo g_{6} (\frac{( x y ) ^{6}}{z})^{4}

ln (\frac{e ^{4 x}}{x ^{2} + 1})

ln (6.56 \cdot 1 0^{- 4})

What is 20e^{3(3)}-ln|3-9|+2ln(3)+50 ?
The solution to 20e^{3(3)}-ln|3-9|+2ln(3)+50 is 20e^9+ln(3/2)+50