What are the solutions to the equation 4x^2=32 ?

The solutions to the equation 4x^2=32 are x=2sqrt(2),x=-2sqrt(2)

Find the zeros of 4x^2=32

The zeros of 4x^2=32 are x=2sqrt(2),x=-2sqrt(2)

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4 x^{2} = 32

x = 22, x = - 22

Solution steps

4 x^{2} = 32

Divide both sides by

4

x^{2} = 8

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 8, x = - 8

8 = 22

- 8 = - 22

x = 22, x = - 22

8 \frac{- 2}{3}

(i - 5)^{2}

8 - 8 d^{2}

\frac{7 x + 5}{- 3} \leq 5 x + 2

b + 19.64 \leq 1.64

What are the solutions to the equation 4x^2=32 ?
The solutions to the equation 4x^2=32 are x=2sqrt(2),x=-2sqrt(2)
Find the zeros of 4x^2=32
The zeros of 4x^2=32 are x=2sqrt(2),x=-2sqrt(2)