What is log_{e}(((1-sin(y)))/(cos(2y))) ?

The solution to log_{e}(((1-sin(y)))/(cos(2y))) is ln(1-sin(y))-ln(cos(2y))

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simplify log_{e}(((1-sin(y)))/(cos(2y)))

simplify

lo g_{e} (\frac{( 1 - sin ( y ) )}{cos ( 2 y )})

ln (1 - sin (y)) - ln (cos (2 y))

Solution steps

lo g_{e} (\frac{( 1 - sin ( y ) )}{cos ( 2 y )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{e} (\frac{( 1 - sin ( y ) )}{cos ( 2 y )}) = lo g_{e} ((1 - sin (y))) - lo g_{e} (cos (2 y))

= lo g_{e} (- sin (y) + 1) - lo g_{e} (cos (2 y))

Apply log rule:

lo g_{e} (x) = ln (x)

= ln (- sin (y) + 1) - lo g_{e} (cos (2 y))

Apply log rule:

lo g_{e} (x) = ln (x)

= ln (- sin (y) + 1) - ln (cos (2 y))

\frac{1}{3} (ln (4) - ln (3))

lo g_{10} (2 \cdot s (1 - y) [y (2 - y)]^{(s - 1)})

- lo g_{10} (8.15 \cdot 1 0^{- 4})

\frac{ln ( 5.435 ) + ln ( 5.429 )}{2}

ln (\frac{5 ^{3}}{3})

What is log_{e}(((1-sin(y)))/(cos(2y))) ?
The solution to log_{e}(((1-sin(y)))/(cos(2y))) is ln(1-sin(y))-ln(cos(2y))