What are the solutions to the equation (4x-1)^2=20 ?

The solutions to the equation (4x-1)^2=20 are x=(2sqrt(5)+1)/4 ,x=(-2sqrt(5)+1)/4

Find the zeros of (4x-1)^2=20

The zeros of (4x-1)^2=20 are x=(2sqrt(5)+1)/4 ,x=(-2sqrt(5)+1)/4

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(4 x - 1)^{2} = 20

x = \frac{2 5 + 1}{4}, x = \frac{- 2 5 + 1}{4}

Decimal Notation

x = 1.36803 \dots, x = - 0.86803 \dots

Solution steps

(4 x - 1)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x - 1 = 20 : x = \frac{2 5 + 1}{4}

Solve

4 x - 1 = - 20 : x = \frac{- 2 5 + 1}{4}

The solutions to the quadratic equation are:

x = \frac{2 5 + 1}{4}, x = \frac{- 2 5 + 1}{4}

0 = x^{2} + 2 x - 3

\frac{2 ( 1 )}{1 + 4}

53

\frac{4 x + 8}{5} < 4

\frac{x ^{7} y ^{- 4}}{x ^{- 2} y ^{- 6}}

What are the solutions to the equation (4x-1)^2=20 ?
The solutions to the equation (4x-1)^2=20 are x=(2sqrt(5)+1)/4 ,x=(-2sqrt(5)+1)/4
Find the zeros of (4x-1)^2=20
The zeros of (4x-1)^2=20 are x=(2sqrt(5)+1)/4 ,x=(-2sqrt(5)+1)/4