What is 21ln(11)+ln(x)+ln(29) ?

The solution to 21ln(11)+ln(x)+ln(29) is ln(11^{21}x*29)

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simplify 21ln(11)+ln(x)+ln(29)

simplify

21 ln (11) + ln (x) + ln (29)

ln (1 1^{21} x \cdot 29)

Solution steps

21 ln (11) + ln (x) + ln (29)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

21 ln (11) = ln (1 1^{21})

= ln (1 1^{21}) + ln (x) + ln (29)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (1 1^{21}) + ln (x) = ln (1 1^{21} x)

= ln (1 1^{21} x) + ln (29)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

ln (1 1^{21} x) + ln (29) = ln (1 1^{21} \cdot 29 x)

= ln (1 1^{21} x \cdot 29)

ln (\frac{8 x - 2}{x + 2} sin (e^{2 x}))

3 ln ∣ x + 2 ∣ + 2 ln ∣ x - 2 ∣

8.314 \cdot 298 \cdot (ln (0.03 3^{5}) - ln (0.74 9^{5}))

ln (\frac{1}{4 x - 10})

ln (\frac{3.64}{23}) + \frac{2 \cdot 2}{23}

What is 21ln(11)+ln(x)+ln(29) ?
The solution to 21ln(11)+ln(x)+ln(29) is ln(11^{21}x*29)