What is 5/7 (x-3)>= 4x+22/7 ?

The solution to 5/7 (x-3)>= 4x+22/7 is x<=-37/23

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5/7 (x-3)>= 4x+22/7

\frac{5}{7} (x - 3) \geq 4 x + \frac{22}{7}

x \leq - \frac{37}{23}

Interval Notation

(- \infty, - \frac{37}{23}]

Decimal Notation

x \leq - 1.60869 \dots

Solution steps

\frac{5}{7} (x - 3) \geq 4 x + \frac{22}{7}

Expand

\frac{5}{7} (x - 3) : \frac{5}{7} x - \frac{15}{7}

\frac{5}{7} x - \frac{15}{7} \geq 4 x + \frac{22}{7}

Move

\frac{15}{7}

to the right side

\frac{5}{7} x \geq 4 x + \frac{37}{7}

Move

4 x

to the left side

- \frac{23}{7} x \geq \frac{37}{7}

Multiply both sides by

- 1

\frac{23}{7} x \leq - \frac{37}{7}

Multiply both sides by

7

23 x \leq - 37

Divide both sides by

23

x \leq - \frac{37}{23}

6 x^{3} + 3 x \geq 4 x^{2} + 2

(- 2 r^{3} p^{2} m)^{3}

w^{2} + 10 w + 21

2 (y + 7) - 4 (y + 3) < 15 (y - 1)

4 x^{2} + 13 x + 9