What are the solutions to the equation x^2-8x+16=81 ?

The solutions to the equation x^2-8x+16=81 are x=13,x=-5

Find the zeros of x^2-8x+16=81

The zeros of x^2-8x+16=81 are x=13,x=-5

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x^{2} - 8 x + 16 = 81

x = 13, x = - 5

Solution steps

x^{2} - 8 x + 16 = 81

Move

81

to the left side

x^{2} - 8 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 65 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 65) = 18

x_{1, 2} = \frac{- ( - 8 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 18}{2 \cdot 1}

x = \frac{- ( - 8 ) + 18}{2 \cdot 1} : 13

x = \frac{- ( - 8 ) - 18}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 13, x = - 5

32 m^{2} - 200

\frac{x + \frac{16}{x + 8}}{x - \frac{4}{x + 8}}

\frac{5}{8} \cdot \frac{8}{9}

14 = 5 x^{2} - x - 4

0 = 3 (x - 4)^{2} - 5

What are the solutions to the equation x^2-8x+16=81 ?
The solutions to the equation x^2-8x+16=81 are x=13,x=-5
Find the zeros of x^2-8x+16=81
The zeros of x^2-8x+16=81 are x=13,x=-5