What is 12(ln|(4)+2|-ln|(4)+3|)+C ?

The solution to 12(ln|(4)+2|-ln|(4)+3|)+C is 12ln(6/7)+C

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simplify 12(ln|(4)+2|-ln|(4)+3|)+C

simplify

12 (ln ∣ (4) + 2 ∣ - ln ∣ (4) + 3 ∣) + C

12 ln (\frac{6}{7}) + C

Solution steps

12 (ln ∣ (4) + 2 ∣ - ln ∣ (4) + 3 ∣) + C

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ (4) + 2 ∣ - ln ∣ (4) + 3 ∣ = ln (\frac{∣ 4 + 2 ∣}{∣ 4 + 3 ∣})

= 12 ln (\frac{∣ 4 + 2 ∣}{∣ 4 + 3 ∣}) + C

\frac{∣ ( 4 ) + 2 ∣}{∣ ( 4 ) + 3 ∣} = \frac{6}{7}

= 12 ln (\frac{6}{7}) + C

y [ln (2 y) - ln (1 - 2 y)] - y [ln (y) - ln (1 - y)]

ln (\frac{60}{120})

ln (- 4.2664 \cdot 1 0^{-} 6)

\frac{1}{10} ln (5000)

\frac{9}{10} ln (2 x + 4) - \frac{12}{5} ln (x + 3)

What is 12(ln|(4)+2|-ln|(4)+3|)+C ?
The solution to 12(ln|(4)+2|-ln|(4)+3|)+C is 12ln(6/7)+C