What is 1.5-[log_{9}(t)+3log_{9}(p)] ?

The solution to 1.5-[log_{9}(t)+3log_{9}(p)] is 1.5-log_{9}(t)-3log_{9}(p)

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simplify 1.5-[log_{9}(t)+3log_{9}(p)]

simplify

1.5 - [lo g_{9} (t) + 3 lo g_{9} (p)]

1.5 - lo g_{9} (t) - 3 lo g_{9} (p)

Solution steps

1.5 - (lo g_{9} (t) + 3 lo g_{9} (p))

Apply the distributive law:

- (a + b) = - a - b

- (lo g_{9} (t) + 3 lo g_{9} (p)) = - lo g_{9} (t) - 3 lo g_{9} (p)

= 1.5 - lo g_{9} (t) - 3 lo g_{9} (p)

ln ((5 e)^{9}) - ln ((6 e)^{8})

lo g_{10} (\frac{4 π}{23})

ln (379 e^{2 x + 3} e^{y + 5})

lo g_{10} (\frac{3}{y x})

6 ln (a x)

What is 1.5-[log_{9}(t)+3log_{9}(p)] ?
The solution to 1.5-[log_{9}(t)+3log_{9}(p)] is 1.5-log_{9}(t)-3log_{9}(p)