What is 1/(2*(0.15*10^{-9))}*ln(1/(0.02)) ?

The solution to 1/(2*(0.15*10^{-9))}*ln(1/(0.02)) is -(1000000000)/(0.3)ln(0.02)

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Popular >

simplify 1/(2(0.1510^{-9))}*ln(1/(0.02))

simplify

\frac{1}{2 \cdot ( 0.15 \cdot 1 0 ^{- 9} )} \cdot ln (\frac{1}{0.02})

- \frac{1000000000}{0.3} ln (0.02)

Decimal Notation

13040076684.760487

Solution steps

\frac{1}{2 ( 0.15 \cdot 1 0 ^{- 9} )} ln (\frac{1}{0.02})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{0.02}) = ln (1) - ln (0.02)

= \frac{1}{1 0 ^{- 9} \cdot 2 \cdot 0.15} (ln (1) - ln (0.02))

\frac{1}{2 \cdot 0.15 \cdot 1 0 ^{- 9}} = \frac{1000000000}{0.3}

= \frac{1000000000}{0.3} (ln (1) - ln (0.02))

Apply log rule:

lo g_{a} (1) = 0

= \frac{1000000000}{0.3} (- ln (0.02) + 0)

0 - ln (0.02) = - ln (0.02)

= \frac{1000000000}{0.3} (- ln (0.02))

Remove parentheses:

(- a) = - a

= - \frac{1000000000}{0.3} ln (0.02)

lo g_{10} (\frac{2 ( 7 + x ) ^{4}}{x ^{5}})

lo g_{g} (\frac{1}{g ^{3}})

ln (x^{2}) + ln^{2} (x)

lo g_{2} ((x - 4)^{3}) + lo g_{2} (x - 4) - 1

- lo g_{10} (2 \cdot 1 0^{(- 4)})

What is 1/(2*(0.15*10^{-9))}*ln(1/(0.02)) ?
The solution to 1/(2*(0.15*10^{-9))}*ln(1/(0.02)) is -(1000000000)/(0.3)ln(0.02)