What is ln((x^4-1)/(x^2-1)) ?

The solution to ln((x^4-1)/(x^2-1)) is ln(x^4-1)-ln(x^2-1)

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simplify ln((x^4-1)/(x^2-1))

simplify

ln (\frac{x ^{4} - 1}{x ^{2} - 1})

ln (x^{4} - 1) - ln (x^{2} - 1)

Solution steps

ln (\frac{x ^{4} - 1}{x ^{2} - 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{x ^{4} - 1}{x ^{2} - 1}) = ln (x^{4} - 1) - ln (x^{2} - 1)

= ln (x^{4} - 1) - ln (x^{2} - 1)

ln (3 e^{2 t})

ln (\frac{x}{17 x - x})

\frac{1}{2} ln (3 - 22) - \frac{1}{2} ln (3 + 22)

- ln (\frac{1}{( 5 x + 7 )})

- 3 ln (x) + \frac{1}{2} ln (y) + ln (z)

What is ln((x^4-1)/(x^2-1)) ?
The solution to ln((x^4-1)/(x^2-1)) is ln(x^4-1)-ln(x^2-1)