What is 4log_{2}(c)-8log_{2}(n) ?

The solution to 4log_{2}(c)-8log_{2}(n) is log_{2}((c^4)/(n^8))

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simplify 4log_{2}(c)-8log_{2}(n)

simplify

4 lo g_{2} (c) - 8 lo g_{2} (n)

lo g_{2} (\frac{c ^{4}}{n ^{8}})

Solution steps

4 lo g_{2} (c) - 8 lo g_{2} (n)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{2} (c) = lo g_{2} (c^{4})

= lo g_{2} (c^{4}) - 8 lo g_{2} (n)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

8 lo g_{2} (n) = lo g_{2} (n^{8})

= lo g_{2} (c^{4}) - lo g_{2} (n^{8})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{2} (c^{4}) - lo g_{2} (n^{8}) = lo g_{2} (\frac{c ^{4}}{n ^{8}})

= lo g_{2} (\frac{c ^{4}}{n ^{8}})

ln (\frac{- x ^{6}}{y ^{6}})

- (\frac{5}{6}) \cdot lo g_{2} (\frac{5}{6}) - (\frac{1}{6}) \cdot lo g_{2} (\frac{1}{6})

2 ln (8) + 3 ln (z)

0.78 - \frac{0.05916}{4} lo g_{10} (\frac{1}{( \frac{1}{x} ) ^{2}})

36 (ln (12) - ln (5))

What is 4log_{2}(c)-8log_{2}(n) ?
The solution to 4log_{2}(c)-8log_{2}(n) is log_{2}((c^4)/(n^8))