What is 5/3 (2x+2)-1/2 (2x-3)>= 2/3 (2x+3) ?

The solution to 5/3 (2x+2)-1/2 (2x-3)>= 2/3 (2x+3) is x>=-17/6

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5/3 (2x+2)-1/2 (2x-3)>= 2/3 (2x+3)

\frac{5}{3} (2 x + 2) - \frac{1}{2} (2 x - 3) \geq \frac{2}{3} (2 x + 3)

x \geq - \frac{17}{6}

Interval Notation

[- \frac{17}{6}, \infty)

Decimal Notation

x \geq - 2.83333 \dots

Solution steps

\frac{5}{3} (2 x + 2) - \frac{1}{2} (2 x - 3) \geq \frac{2}{3} (2 x + 3)

Expand

\frac{5}{3} (2 x + 2) - \frac{1}{2} (2 x - 3) : \frac{7 x}{3} + \frac{29}{6}

Expand

\frac{2}{3} (2 x + 3) : \frac{4}{3} x + 2

\frac{7 x}{3} + \frac{29}{6} \geq \frac{4}{3} x + 2

Move

\frac{29}{6}

to the right side

\frac{7 x}{3} \geq - \frac{17}{6} + \frac{4}{3} x

Move

\frac{4}{3} x

to the left side

x \geq - \frac{17}{6}

(\frac{1}{9})^{3}

- 9 + x = - 26

- 3 x^{2} - 6 x + 9 = 0

6 b^{2 n + 1} + 5 b^{n + 1} - 6 b

3 p^{2} + 14 p + 8

What is 5/3 (2x+2)-1/2 (2x-3)>= 2/3 (2x+3) ?
The solution to 5/3 (2x+2)-1/2 (2x-3)>= 2/3 (2x+3) is x>=-17/6