What is ln(e^{-x}cos^2(x))-ln(x^2+x+1) ?

The solution to ln(e^{-x}cos^2(x))-ln(x^2+x+1) is ln((e^{-x}cos^2(x))/(x^2+x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(e^{-x}cos^2(x))-ln(x^2+x+1)

simplify

ln (e^{- x} cos^{2} (x)) - ln (x^{2} + x + 1)

ln (\frac{e ^{- x} cos ^{2} ( x )}{x ^{2} + x + 1})

Solution steps

ln (e^{- x} cos^{2} (x)) - ln (x^{2} + x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (e^{- x} cos^{2} (x)) - ln (x^{2} + x + 1) = ln (\frac{e ^{- x} cos ^{2} ( x )}{x ^{2} + x + 1})

= ln (\frac{e ^{- x} cos ^{2} ( x )}{x ^{2} + x + 1})

ln (- 1.04 \cdot (- 2 + 0.06))

ln (2.8 \cdot \frac{( 12 - 1.8 )}{1.8 \cdot ( 12 - 2.8 )})

ln (a^{c} b^{g})

- \frac{8.31 \cdot 310}{1 \cdot 9.65 \cdot 1 0 ^{- 4}} \cdot ln (\frac{10}{145})

ln (2) + ln (2) - ln (3)

What is ln(e^{-x}cos^2(x))-ln(x^2+x+1) ?
The solution to ln(e^{-x}cos^2(x))-ln(x^2+x+1) is ln((e^{-x}cos^2(x))/(x^2+x+1))