What are the solutions to the equation 0=3x^2-3 ?

The solutions to the equation 0=3x^2-3 are x=1,x=-1

Find the zeros of 0=3x^2-3

The zeros of 0=3x^2-3 are x=1,x=-1

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0 = 3 x^{2} - 3

x = 1, x = - 1

Solution steps

0 = 3 x^{2} - 3

Switch sides

3 x^{2} - 3 = 0

Move

3

to the right side

3 x^{2} = 3

Divide both sides by

3

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

(x^{2})^{\frac{2}{5}}

6 p^{2} + 5 p + 1

12.3 = 0.41 x

- \frac{3}{2} < \frac{x - 3}{4} \leq \frac{5}{4}

4 x + 1 > 13

What are the solutions to the equation 0=3x^2-3 ?
The solutions to the equation 0=3x^2-3 are x=1,x=-1
Find the zeros of 0=3x^2-3
The zeros of 0=3x^2-3 are x=1,x=-1