What is 20log_{10}((5*10^{-3})/2)+4 ?

The solution to 20log_{10}((5*10^{-3})/2)+4 is 20(-log_{10}(200)-log_{10}(2))+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 20log_{10}((5*10^{-3})/2)+4

simplify

20 lo g_{10} (\frac{5 \cdot 1 0 ^{- 3}}{2}) + 4

20 (- lo g_{10} (200) - lo g_{10} (2)) + 4

Decimal

- 48.04119 \dots

Solution steps

20 lo g_{10} (\frac{5 \cdot 1 0 ^{- 3}}{2}) + 4

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{5 \cdot 1 0 ^{- 3}}{2}) = lo g_{10} (5 \cdot 1 0^{- 3}) - lo g_{10} (2)

= 20 (lo g_{10} (1 0^{- 3} \cdot 5) - lo g_{10} (2)) + 4

lo g_{10} (5 \cdot 1 0^{- 3}) = - lo g_{10} (200)

= 20 (- lo g_{10} (2) - lo g_{10} (200)) + 4

ln (\frac{e ^{6}}{2})

- \frac{1}{3} ln (6)

ln x^{2} + 1 + x^{4} - ln 4 + 17

2 ln (4 x)

lo g_{8} (\frac{( ab ) 3}{c ^{5}})

What is 20log_{10}((5*10^{-3})/2)+4 ?
The solution to 20log_{10}((5*10^{-3})/2)+4 is 20(-log_{10}(200)-log_{10}(2))+4