What is log_{y}(2e^5)-log_{y}(5e^8) ?

The solution to log_{y}(2e^5)-log_{y}(5e^8) is log_{y}(2/(5e^3))

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simplify log_{y}(2e^5)-log_{y}(5e^8)

simplify

lo g_{y} (2 e^{5}) - lo g_{y} (5 e^{8})

lo g_{y} (\frac{2}{5 e ^{3}})

Solution steps

lo g_{y} (2 e^{5}) - lo g_{y} (5 e^{8})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{y} (2 e^{5}) - lo g_{y} (5 e^{8}) = lo g_{y} (\frac{2 e ^{5}}{5 e ^{8}})

= lo g_{y} (\frac{2 e ^{5}}{5 e ^{8}})

\frac{2 e ^{5}}{5 e ^{8}} = \frac{2}{5 e ^{3}}

= lo g_{y} (\frac{2}{5 e ^{3}})

\frac{3}{4} (ln (7) - ln (5))

ln (\frac{y ^{2}}{2 y})

lo g_{\frac{1}{2} (\frac{3}{5}),} (x)

lo g_{9} (7 \cdot 5 \cdot 1 2^{5})

lo g_{8} ((\frac{u ^{6}}{v})^{4})

What is log_{y}(2e^5)-log_{y}(5e^8) ?
The solution to log_{y}(2e^5)-log_{y}(5e^8) is log_{y}(2/(5e^3))