What is 1*log_{10}(0.65)+(1-1)*log_{10}(1-0.65) ?

The solution to 1*log_{10}(0.65)+(1-1)*log_{10}(1-0.65) is log_{10}(13/20)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1log_{10}(0.65)+(1-1)log_{10}(1-0.65)

simplify

1 \cdot lo g_{10} (0.65) + (1 - 1) \cdot lo g_{10} (1 - 0.65)

lo g_{10} (\frac{13}{20})

Decimal Notation

- 0.18708 \dots

Solution steps

1 \cdot lo g_{10} (0.65) + (1 - 1) lo g_{10} (1 - 0.65)

1 \cdot lo g_{10} (0.65) = lo g_{10} (\frac{13}{20})

(1 - 1) lo g_{10} (1 - 0.65) = 0

= lo g_{10} (\frac{13}{20}) + 0

Apply rule:

a + 0 = a

= lo g_{10} (\frac{13}{20})

ln (x) + ln (y) + 2 ln (12 - x - y)

ln (\frac{x}{( x + 1 )})

\frac{2}{3} lo g_{2} (x) + lo g_{2} (y)

89.9 (- ln ∣ 0.3 + 0.2 ∣ + ln ∣ 0.2 ∣)

\frac{18}{16 π ^{2}} ln (\frac{( 16 ) ^{2}}{0.03 \cdot 16 π ^{2}})

What is 1*log_{10}(0.65)+(1-1)*log_{10}(1-0.65) ?
The solution to 1*log_{10}(0.65)+(1-1)*log_{10}(1-0.65) is log_{10}(13/20)