What is log_{4}(5)+log_{4}(1.25) ?

The solution to log_{4}(5)+log_{4}(1.25) is log_{2}(5)-1

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simplify log_{4}(5)+log_{4}(1.25)

simplify

lo g_{4} (5) + lo g_{4} (1.25)

lo g_{2} (5) - 1

Decimal Notation

1.32192 \dots

Solution steps

lo g_{4} (5) + lo g_{4} (1.25)

lo g_{4} (1.25) = lo g_{4} (5) - 1

= lo g_{4} (5) + lo g_{4} (5) - 1

Add similar elements:

lo g_{4} (5) + lo g_{4} (5) = 2 lo g_{4} (5)

= 2 lo g_{4} (5) - 1

2 lo g_{4} (5) = lo g_{2} (5)

= lo g_{2} (5) - 1

0.56 + 0.026 \cdot ln (\frac{1 0 ^{16}}{1.5 \cdot 1 0 ^{10}})

ln (\frac{1}{2 π x ^{2 n}})

- lo g_{10} (11.58 \cdot 1 0^{- 5})

lo g_{2} (8 e^{+ 9})

ln (\frac{1 + e ^{x + 2 y}}{e ^{x + 2 y}})

What is log_{4}(5)+log_{4}(1.25) ?
The solution to log_{4}(5)+log_{4}(1.25) is log_{2}(5)-1