What is 10log_{10}(((2.5)^2)/(1000))+40+59 ?

The solution to 10log_{10}(((2.5)^2)/(1000))+40+59 is -10log_{10}(160)+99

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simplify 10log_{10}(((2.5)^2)/(1000))+40+59

simplify

10 lo g_{10} (\frac{( 2.5 ) ^{2}}{1000}) + 40 + 59

- 10 lo g_{10} (160) + 99

Decimal Notation

76.95880 \dots

Solution steps

10 lo g_{10} (\frac{2. 5 ^{2}}{1000}) + 40 + 59

Add the numbers:

40 + 59 = 99

= 10 lo g_{10} (\frac{2. 5 ^{2}}{1000}) + 99

10 lo g_{10} (\frac{2. 5 ^{2}}{1000}) = - 10 lo g_{10} (160)

= - 10 lo g_{10} (160) + 99

\frac{1}{0.025} \cdot ln (\frac{100}{2})

ln ∣ s + a ∣ - ln ∣ a ∣

ln (\frac{e ^{7}}{13})

3727.8 ln (\frac{( 23180 + 56088 )}{23180})

360 lo g_{10} (3) - 720 lo g_{10} (5)

What is 10log_{10}(((2.5)^2)/(1000))+40+59 ?
The solution to 10log_{10}(((2.5)^2)/(1000))+40+59 is -10log_{10}(160)+99