What is (-ln(x+2)+ln(x))/4+1/(2x+4) ?

The solution to (-ln(x+2)+ln(x))/4+1/(2x+4) is (ln(x/(x+2)))/4+1/(2x+4)

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simplify (-ln(x+2)+ln(x))/4+1/(2x+4)

simplify

\frac{- ln ( x + 2 ) + ln ( x )}{4} + \frac{1}{2 x + 4}

\frac{ln ( \frac{x}{x + 2} )}{4} + \frac{1}{2 x + 4}

Solution steps

\frac{- ln ( x + 2 ) + ln ( x )}{4} + \frac{1}{2 x + 4}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (x) - ln (x + 2) = ln (\frac{x}{x + 2})

= \frac{ln ( \frac{x}{x + 2} )}{4} + \frac{1}{2 x + 4}

e^{2 l n ∣ l n (x) ∣ + l n (x)}

lo g_{10} (1.2 e^{- 3})

ln (A e^{\frac{3}{2} t^{2}})

ln ∣ 4 ∣ + 2 ln (4^{2} + 4) - ln ∣ 1 ∣ + 2 ln (1^{2} + 4)

What is (-ln(x+2)+ln(x))/4+1/(2x+4) ?
The solution to (-ln(x+2)+ln(x))/4+1/(2x+4) is (ln(x/(x+2)))/4+1/(2x+4)