What is simplify-*ln((v_{1})/(v_{4)}) ?

The solution to simplify-*ln((v_{1})/(v_{4)}) is -ln(v_{1})+ln(v_{4})

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify-*ln((v_{1})/(v_{4)})

simplify

- \cdot ln (\frac{v _{1}}{v _{4}})

- ln (v_{1}) + ln (v_{4})

Solution steps

- ln (\frac{v _{1}}{v _{4}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{v _{1}}{v _{4}}) = ln (v_{1}) - ln (v_{4})

= - (ln (v_{1}) - ln (v_{4}))

Distribute parentheses

= - (ln (v_{1})) - (- ln (v_{4}))

Apply minus-plus rules

- (- a) = a, - (a) = - a

= - ln (v_{1}) + ln (v_{4})

ln (\frac{643}{30})

ln (\frac{70}{50}) + (\frac{1}{2} \cdot 0. 2^{2} - 0.01) \cdot 4

ln ∣ y ∣ + ln ∣ x ∣

\frac{1}{2} lo g_{10} (2) + \frac{1}{2} lo g_{10} (5)

[2 ln (3) - 2 ln (9)] - [2 ln (2) - 2 ln (7)]

What is simplify-*ln((v_{1})/(v_{4)}) ?
The solution to simplify-*ln((v_{1})/(v_{4)}) is -ln(v_{1})+ln(v_{4})