What is 1/(ln(2))*ln(4/3) ?

The solution to 1/(ln(2))*ln(4/3) is (2ln(2)-ln(3))/(ln(2))

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simplify 1/(ln(2))*ln(4/3)

simplify

\frac{1}{ln ( 2 )} \cdot ln (\frac{4}{3})

\frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 2 )}

Decimal Notation

0.41503 \dots

Solution steps

\frac{1}{ln ( 2 )} ln (\frac{4}{3})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{4}{3}) = ln (4) - ln (3)

= \frac{1}{ln ( 2 )} (ln (4) - ln (3))

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( ln ( 4 ) - ln ( 3 ) )}{ln ( 2 )}

1 \cdot (ln (4) - ln (3)) = ln (4) - ln (3)

= \frac{ln ( 4 ) - ln ( 3 )}{ln ( 2 )}

ln (4) = 2 ln (2)

= \frac{2 ln ( 2 ) - ln ( 3 )}{ln ( 2 )}

(0.287) ln (\frac{500}{200}) - (1.05) ln (\frac{680}{980})

lo g_{e} (25) + lo g_{e} (4)

\frac{8}{5} ln (\frac{4}{3}) + \frac{9}{10} ln (\frac{81}{77})

0.615 + 0.1 lo g_{10} (\frac{2.19}{2.15})

ln (\frac{x ^{2} + 1 - x}{x ^{2} + 1 + x})

What is 1/(ln(2))*ln(4/3) ?
The solution to 1/(ln(2))*ln(4/3) is (2ln(2)-ln(3))/(ln(2))